Dear All,
After running Mean-Centering PLS we identified a significant LV (55.42% crossblock, p < 0.000, CI bars do not cross zero) then we tried to reproduce the same result with the Non-rotated Task PLS with a contrast reflecting the design obtained with mean-centering. The Non-Rotated results provided an LV with 49.81% Crossblock, p < 0.000 but with CI bars crossing zero (see attached file). Any idea on why this could be happening?
Many thanks in advance,
Best regards,
MohamedLogin to reply to this topic.
Yes, its an issue with mean-centreing in the non-rotated analysis. Can you run it without mean-centering?
Yes, its an issue with mean-centreing in the non-rotated analysis. Can you run it without mean-centering?
Many thanks for your answer!
which option for that 0,1,2,3?
Many thanks for your answer!
which option for that 0,1,2,3?
Sorry, I misrembered the options - there isn't one for no mean correction (you'd think I would know that). I thought we fixed this in the latest version to do non-rotated PLS with no mean centering.
Can you repost the screen shot of the non-rotated result? That didnt make it on your last posting. Alternatively, send me an email: rmcintosh@research.baycrest.org and I will post my reply here.
Randy
Sorry, I misrembered the options - there isn't one for no mean correction (you'd think I would know that). I thought we fixed this in the latest version to do non-rotated PLS with no mean centering.
Can you repost the screen shot of the non-rotated result? That didnt make it on your last posting. Alternatively, send me an email: rmcintosh@research.baycrest.org and I will post my reply here.
Randy
Mohamed
Mohamed
Mohamed
hi there
On the permutation and bootstrap issue, more iterations are always better and since computing power is cheap its probably better to rerun with more permutations than argue. It will likely not make a difference. As for the threshold, the bootstrap is not meant to be a null hypothesis test but one of reliability. We made a point of this in the McIntosh & Lobaugh 2004 review paper.
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